A swimming pool fitted with three pipes of uniform flow.The first two pipes operating simultaneously, fill the pool in the same time as the time taken by third pipe alone to fill the pool.The second pipe fills the pool five hours faster than the first pipe and four hour slower than the third pipe.find the time required by first pipe to fill the pool?
a)10 hours
b)17 hours
c)15 hours
d)11 hours
e)14.5 hours
Yaa can ny1 tell a shortcut !!!
15
C is the answer..
1/x + 1/y = 1/z
1/y = 1/x-5
1/y = 1/z+4
solving them gives x=15
but i guess i’ve used a lengthier way. anyone has a shorter way to solve it?
C
C