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n people are seated on the round table, and jack and mary are two of them. One person of the n people is selected for the prize..
Col A
The probablity that in the seating arrangement jack and mary come together.
Col B
The probability to select one person for the prize.
A) If the quantity in column A is [...]
Written by Take GRE Team on March 9th, 2008 with
9 comments.
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n people are seated on the round table, and jack and mary are two of them. One person of the n people is selected for the prize..
Col A
The probablity that in the seating arrangement jack and mary come together.
Col B
The probability to select one person for the prize.
A) If the quantity in column A is greater.
B) If the quantity in column B is greater.
C) If the quantities are equal.
D) If the relationship cannot be determined from the information given.
GRE Question of the Day by Take GRE Team on March 9th, 2008 with
9 answers.
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Read the answer left by other GRE Takers below, or:
Neel
#2.
November 27th, 2006, at 2:17 PM.
ans.:A
Ritesh
#3.
December 5th, 2006, at 3:04 PM.
D…
eg.
colA will be (n-2)!x2!
colB will be n
if n=3 ,
A
Sunjana
#4.
March 9th, 2008, at 10:22 PM.
b
RAJ
#5.
March 11th, 2008, at 10:54 PM.
Sunjana hw it is B…can u explain clr plz
Take GRE Team
#6.
March 12th, 2008, at 4:40 AM.
A.
Achilles
#7.
March 12th, 2008, at 9:05 AM.
Ans is A
Col A : When you are in a round table the total number of ways in which
Jack and Mary can sit is (n-1). (Try with four 4 people)
Among them only one arrangement has Jack and Mary next to
each other. So the probability is 1/(n-1)
Col B : To select one person from n, the probability is 1/n
Clearly, col A > col B
gupta
#8.
May 12th, 2008, at 12:11 AM.
@ Achilles… u forgot the rearrangement between both dude….
anuways.. answer wud be A
Sweta
#9.
June 30th, 2008, at 10:49 PM.
Col A: {(n-2)!* 2!}/(n-1)! = 2/(n-1)
Col B: 1/(n-1)
Therefore, Col A is greater.
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#1. November 15th, 2006, at 4:53 PM.
d