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GRE Question of The Day: Time and Work

Three printing presses, R, S, and T, working together at their respective constant rates, can do a certain printing job in 4 hours. S and T, working together at their respective constant rates, can do the same job in 5 hours. How many hours would it take R, working alone at its constant [...]

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Written by Take GRE Team on April 20th, 2007 with 6 comments.
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Three printing presses, R, S, and T, working together at their respective constant rates, can do a certain printing job in 4 hours. S and T, working together at their respective constant rates, can do the same job in 5 hours. How many hours would it take R, working alone at its constant rate, to do the same job?

A) 8
B) 10
C) 12
D) 15
E) 20

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GRE Question of the Day by Take GRE Team on April 20th, 2007 with 6 answers.
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6 Answers

Read the answer left by other GRE Takers below, or:

Get your own gravatar by visiting gravatar.com lee
#1. July 23rd, 2006, at 1:14 PM.

E)20

Get your own gravatar by visiting gravatar.com den
#2. July 23rd, 2006, at 5:35 PM.

R — r hrs …. 1 work
1 hr — 1/r of work

1 hr — > 1/r + 1/s + 1/t = 1/4
1/r + 1/5 = 1/4
r =20

Get your own gravatar by visiting gravatar.com sateesh_rahul
#3. July 24th, 2006, at 12:10 AM.

answer=20

GIVEN
1/r+1/s+1/t=1/4

1/s+1/t=1/5

so..1/s=1/4-1/5=1/20..
so in a dat s can do 1/20 of work..so it takes 20 days for full work

Get your own gravatar by visiting gravatar.com hesperus
#4. July 24th, 2006, at 12:25 AM.

20

Get your own gravatar by visiting gravatar.com Take GRE Team
#5. July 24th, 2006, at 6:26 AM.

any simple approach pls

Get your own gravatar by visiting gravatar.com yadav
#6. April 20th, 2007, at 7:24 PM.

i think this is the simplest.
as mentoned by sateesh
1/r+1/s+1/t=1/4

1/s+1/t=1/5

so..1/s=1/4-1/5=1/20..

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