GRE Question of The Day:A man has 7 relatives

A man has 7 relatives, 4 of them are ladies and 3 gentlemen; his wife has also 7 relatives; 3 of them are ladies and 4 gentlemen. In how many ways can they invite a dinner party of 3 ladies and 3 gentlemen so that there are 3 of the man’s relative and 3of the [...]

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Written by Take GRE Team on September 4th, 2008 with 8 comments.
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The best study material for scoring 1500 in GRE.

(a)485

(b)480

(d) 520

(e) None of these.

GRE Question of the Day by Take GRE Team on September 4th, 2008 with 8 answers.
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8 Answers

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Vandana
#1. August 7th, 2006, at 5:19 PM.

its (a) 485
here it goes..
4c3 * 4c3 = 1
4c1 * 3c2 * 4c1 * 3c2 = 144
4c2 * 3c1 * 4c2 * 3c2 = 324
4c1 * 4c1 = 16 so all the options i hav taken
nw if we add all these i.e. 1 + 144 + 324 + 16 = 485
is it rite..

chris
#2. August 7th, 2006, at 9:48 PM.

yups the ans is a

shan
#3. August 23rd, 2006, at 12:18 PM.

Answer is A

Ritesh
#4. December 5th, 2006, at 4:27 PM.

A is the rite answer

Tena Rytel
#5. September 12th, 2008, at 11:49 PM.

Vandana- can you explain your math- what is c1, c2, c3… Thanks

saha
#6. September 13th, 2008, at 7:57 PM.

the ans is A 485
manside lady side total

4c3 (lady) 4c3(gents) 4c3*4c3 = 16
4c2*3c1 3c1*4c2 4c2*3c1*3c1*4c2 = 324
(2L)(1G) (1L)(2G) similarly

4c1*3c2 3c2*4c1 4c1*3c2*3c2*4c1 = 144
(1L)(2G) (2L)(1G)

3c3(gents) 3c3(ladies) 3c3*3c3 = 1
___________________________________
the taotal ways is 16+324+144+1 = 485ways

sm82
#7. September 16th, 2008, at 2:12 AM.

A) 485

sam
#8. September 18th, 2008, at 12:14 AM.

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