Live chatPlease Answer: Area of three non overlapping circle
Column A
Area of three non-overlapping circle with radius 1
Column b
3pi
Written by bhattarai.suni on August 30th, 2008 with
6 comments.
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Column A
Area of three non-overlapping circle with radius 1
Column b
3pi
GRE Question of the Day by bhattarai.suni on August 30th, 2008 with
6 answers.
Read more articles on .
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6 Answers
Read the answer left by other GRE Takers below, or:
anu
#2.
September 4th, 2008, at 11:23 AM.
c is d answer
Pranav
#3.
September 4th, 2008, at 9:04 PM.
the answer is indeed c. This is because if we take column a, the area of 3 non overlaping circles = pi(r^2)+pi(r^2)+pi(r^2) where r is the radius. r=1 here so we get pi(1^2)+pi(1^2)+pi(1^2) = 3pi which is equal to column b.
SM82
#4.
September 4th, 2008, at 10:15 PM.
C for sure.
The 3 circles are non-overlapping. Therefore Area of C1, C2, C3 = pi(r1^2) + pi(r2^2)+ pi(r3^2) where r1=r2=r3=1. Therefore Column A = Area of C1 + C2 + C3 = pi + pi + pi = 3pi = Column 2.
SM82
#5.
September 4th, 2008, at 10:16 PM.
Test GRE team will you please confirm the answer? Its no fun solving w/t knowing if one is doing right or wrong. Thank You!
viki
#6.
September 15th, 2008, at 1:22 PM.
c
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#1. September 4th, 2008, at 7:37 AM.
answer is C