Find the least number which when divided by 36, 48 and 64 leaves the remainders 25, 37 and 53 respectively. ( Consider it as the new types coming up where you have to find the precise answer without any options given)
Problem Solving
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TAKE LCM OF36,48,64=576
NOW SUBTRACT 11 FROM IT=576-11=565
Hi, I have not calculated the answer. But the procedure to solve this kind of problem is explained below.
First see the difference between divisors and corresponding remainder. Here in our case, the respective differences are (36 – 25), (48 – 37) and (64 – 53). So, this is nothing but 11.
So, find out the LCM of 36, 48 and 64. Lets say X. Now X is completely divisible by 36, 48 and 37. If we subtract 11 from X, the resulting number would leave 25, 37 and 53 when divided by 36, 48 and 64 respectively.
Hope, This explanation works.
hi…
I request anyone of you to plzz explain if these kind of questions have been asked in the GRE examination. The other day a question related to combinations was posted.
Thank you
565
Take LCM of 36,48,64 =576
36-25=11 and so on so that means all are 11 less
576-11=565
Subtracting 11 gives the number with the correct remainders, because each given remainder is 11 less than the corresponding divisor.
pls explain…why substracted by 11
i came up with 565 but i used a long cut of creating equations and substituting them…..obviously it was a very time consuming and tedious.
can anyone explain a easier technique.
why subtracted by -11 i did not get the reson for that pls do write about that
ans is 565
ie LCM of 36,48,64 (= 576) -11
Ans:565
Take LCM of 36,48,64 =576
576-11=565
Thanks, looking for more.
Ans:565
Take LCM of 36,48,64 =576
576-11=565