Quant- Problem Solving

What is the value of (4x^3-x)/(2x+1)(6x-3), when x=9999 ?

A) 999999
B) 111111
C) 33333
D) 3333
E) 333

Pls Explain…

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30 Comments Post a Comment
  1. shweta chauhan says:

    its D

  2. Shruti Madan says:

    (4x^3-x)/(2x+1)(6x-3)
    =x(4x^2-1)/(2x+1)3(2x-1) {taking x common outside from
    numerartor n takin 3 common from the
    term 6x-3, from denominator.}
    =x(2x+1)(2x-1)/3(2x+1)(2x-1) {then split numerator 4x^2-1 as
    (2x-1)(2x+1).}
    =x/3
    =9999/3 {substituting value of x(given)}
    =3333
    Atleast now have u understood? (for all those people, who had NOT understood the sum)

  3. Shruti Madan says:

    the answer is D) 3333.

  4. hemanshu_abbey says:

    D

    Factorize and u will c

  5. jainisuni says:

    D

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