What is the value of (4x^3-x)/(2x+1)(6x-3), when x=9999 ?
A) 999999
B) 111111
C) 33333
D) 3333
E) 333
Pls Explain…
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its D
(4x^3-x)/(2x+1)(6x-3)
=x(4x^2-1)/(2x+1)3(2x-1) {taking x common outside from
numerartor n takin 3 common from the
term 6x-3, from denominator.}
=x(2x+1)(2x-1)/3(2x+1)(2x-1) {then split numerator 4x^2-1 as
(2x-1)(2x+1).}
=x/3
=9999/3 {substituting value of x(given)}
=3333
Atleast now have u understood? (for all those people, who had NOT understood the sum)
the answer is D) 3333.
D
Factorize and u will c
D