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hi ,
I need a solution for below mention question with explanation.
1) how many different factors are there for 242 excluding one & itself?
a)3 b)4 c)5 d)6 e)7
2)for how many intergers n is 20-n^2 greater than zero?
a)1 b)2 c)4 d)5 e)9
3)One number is 4 times the another number and their sum is -10.what is the lesser [...]
Written by chinna on October 10th, 2008 with
8 comments.
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hi ,
I need a solution for below mention question with explanation.
1) how many different factors are there for 242 excluding one & itself?
a)3 b)4 c)5 d)6 e)7
2)for how many intergers n is 20-n^2 greater than zero?
a)1 b)2 c)4 d)5 e)9
3)One number is 4 times the another number and their sum is -10.what is the lesser of the two numbers?
a)-2 b)-2.5 c)-7.5 d)-8 e)-10
4)A number when divided by 221 leaves a remainder 64. What is the remainder if the same number is divided by 13?
a)0 b)1 c)7 d)1 e)12
5)how many times should the keys of type writer be pressed in order to write first 400 counting numbers?
a)1082 b)1092 c)1192 d)1200 e)12082
6) how many of the odd integers between 10 and 20 can be expressed as the difference between the squares of two consecutive integers?
a)5 b)4 c)3 d)1 e)0
7) what is the least integer n such that 54/n^3 is even?
a)-3 b)-1 c)1 d)2 e)3
GRE Question of the Day by chinna on October 10th, 2008 with
8 answers.
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kaushik
#2.
October 12th, 2008, at 12:36 PM.
1.a
2.e
3.d
4.e
5.c
6.a
7.a
Gaurav
#3.
October 12th, 2008, at 1:46 PM.
1……B
2……E
3……D
4……E
5……B
6……A
7……A
chandana
#4.
October 13th, 2008, at 11:58 AM.
hi..
1. b
242 = 2^1 * 11^2
no. of factors = (1+1) * (2+1) = (2*3) = 6
no. of factors excluding 1 and itself = 6-2 = 4
2. e
20-n^2
substitute -4,-3,-2,-1,0,1,2,3,4
3. d
4. e
when 221 leaves a remainder of 4 ==> 221m+64 = the number(x)
let m=1, then x = 285
when 285 is divided by 13 the remainder is 12
5. b
1-9 nos one key is pressed for each no ==> 9*1
10 - 99 nos two keys are pressed for each no ==> 90*2
100 - 400 nos three keys are pressed for each no ==> 301*3
total no. of keys pressed = (9*1) + (90*2) + (301*3) = 1092
6. a
the odd integers
11 = 6^2 - 5^2
13 = 7^2 - 6^2
15 = 8^2 - 7^2
17 = 9^2 - 8^2
19 = 10^2 - 9^2
7. a
go from options
substitute -3 for n in 54/n^3
Kofi
#5.
October 13th, 2008, at 6:50 PM.
great guys!
chinna
#6.
October 13th, 2008, at 8:29 PM.
hi chandana,
I appreciate the way you explain..& can you explain the 1st one
no. of factors = (1+1) * (2+1) = (2*3) = 6 —i didn’t understand this step.
badbond
#7.
October 13th, 2008, at 8:33 PM.
factor of 242 is 4,,,,,,,,,,,
i explain 1 and 242 are excluding,,, so 2, 11, 22, 121…
rajiba
#8.
November 12th, 2008, at 3:16 PM.
Two numbers are to be selected from these 10 numbers and they can be same also. What is the probability that at least one of them is even?
A. 1/2
B. 3/4
C. 1/4
D. 1/5
E. 3/2
can anyone help in this question
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#1. October 11th, 2008, at 9:56 PM.
Answers are as follows with Explainations–
1. a
Exp : different factors can be 2,11 or 121 other than the number itself and 1.
2. e
Exp : for the expression 20 - n ^2 the values of n can be -1,1,-2,2,-3,3,-4,4,0. All these are integers.
3. d
Exp : Let one number be x. Other number is 4times the first i.e. 4x. No, sum of these two numbers is -10. Thus, x + 4x = -10 yields x = -2.
and other number as 4 times x i.e. -8. No asked is smaller of the two numbers. Thus -8 is the answer.
4. e
5. c
6. a
7. a